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7x^2-14x-245=0
a = 7; b = -14; c = -245;
Δ = b2-4ac
Δ = -142-4·7·(-245)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7056}=84$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-84}{2*7}=\frac{-70}{14} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+84}{2*7}=\frac{98}{14} =7 $
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